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Date: 9-8-2016
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Conducting Sphere in Constant Magnetic Field
A perfectly conducting sphere of radius R moves with constant velocity through a uniform magnetic field B = B0ŷ (see Figure 1.1). Find the surface charge density induced on the sphere to lowest order in v/c.
Figure 1.1
SOLUTION
In the frame K' moving with velocity v, we have, to lowest order in v/c
(1)
In the lab frame K, we have E = 0 and B = B0ŷ. Using (1) for the frame K', we have an electric field in this frame
(2)
where E'0 = vB0/c. Now, we have a perfectly conducting sphere in a constant electric field, so we may write the potential outside the sphere in the form
(3)
where θ is the angle between r and E', or, in this case, between r and ẑ (the origin of the spherical coordinates is at the center of the sphere). The surface charge density a is given by
Finally, substituting E'0 from (2), we have
(4)
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مخاطر خفية لمكون شائع في مشروبات الطاقة والمكملات الغذائية
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"آبل" تشغّل نظامها الجديد للذكاء الاصطناعي على أجهزتها
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تستخدم لأول مرة... مستشفى الإمام زين العابدين (ع) التابع للعتبة الحسينية يعتمد تقنيات حديثة في تثبيت الكسور المعقدة
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