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Date: 11-6-2018
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Date: 13-6-2018
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Date: 13-6-2018
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To solve the system of differential equations
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(1) |
where is a matrix and
and
are vectors, first consider the homogeneous case with
. The solutions to
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(2) |
are given by
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(3) |
But, by the eigen decomposition theorem, the matrix exponential can be written as
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(4) |
where the eigenvector matrix is
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(5) |
and the eigenvalue matrix is
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(6) |
Now consider
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(7) |
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(8) |
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(9) |
The individual solutions are then
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(10) |
so the homogeneous solution is
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(11) |
where the s are arbitrary constants.
The general procedure is therefore
1. Find the eigenvalues of the matrix (
, ...,
) by solving the characteristic equation.
2. Determine the corresponding eigenvectors , ...,
.
3. Compute
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(12) |
for , ...,
. Then the vectors
which are real are solutions to the homogeneous equation. If
is a
matrix, the complexvectors
correspond to real solutions to the homogeneous equation given by
and
.
4. If the equation is nonhomogeneous, find the particular solution given by
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(13) |
where the matrix is defined by
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(14) |
If the equation is homogeneous so that , then look for a solution of the form
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(15) |
This leads to an equation
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(16) |
so is an eigenvector and
an eigenvalue.
5. The general solution is
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